Let a=⟨−1,−2,3⟩a=⟨−1,−2,3⟩ and b=⟨−5,4,−4⟩b=⟨−5,4,−4⟩. Show that there are scalars ss and tt so that sa+tb=⟨−18,20,−22⟩sa+tb=⟨−18,20,−22 ⟩ You might want to sketch the vectors to get some intuition.

Use the radius you found in part i (r=26.8 cm) with the surface area formula below to find the surface area of the sphere. show your work and round your answer to the nearest tenth. the surface area of a sphere: sa = 4πr^2 self note: 3.8.4

The ksp expression for the system pbcl2(s) pb+2(aq) + 2 cl-(aq) is: [pbc12][pb+2][2cl-] [pb+2][cl-]2 [pb+2][2cl-]2 [pbcl2][pb+2][cl-]2 [pb+2][2cl-]2[pbcl2]

4. (10.03 mc) the equation of line cd is y = −2x − 2. write an equation of a line parallel to line cd in slope-intercept form that contains point (4, 5). (4 points) y = −2x + 13 y = negative 1 over 2 x + 7 y = negative 1 over 2 x + 3 − 2x − 3