Please answer #11,#15,and #16.For #11, determine if the graph represents a function. For #15-16 find the domain and range of the function represented by the graph.

Problem 11

Not a function

Why not? Because it fails the vertical line test. It is possible to draw a single straight vertical line through more than one point on this blue curve.

Put another way: An input like x = 2 produces more than one output (y = 2 and y = 4 at the same time). If we wanted a function, we need any given input in the domain to produce exactly one and only one output.

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Problem 15

Answers:

Explanation:

The domain is the set of allowed x values. The left-most point on the blue curve is when x = -4, which is the smallest item allowed in the domain. The largest value allowed is x = 2, as this occurs at the right-most point on the blue curve. Therefore, our domain here is

The range is similar, but we focus on y values this time. The lowest the graph goes is y = 2, and the highest it goes is y = 6. So represents the range of possible y outputs.

For both the domain and range, both endpoints are included.

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Problem 16

Answers:

Explanation:

We follow the same idea as before. This time however, we have open holes which means that we do not include the endpoints.

The domain is since the curve spans from x = 2 to x = 7, excluding both of those x values. The range is for similar reasoning.

Notice how both problems 15 and 16 are functions because they pass the vertical line test. It is not possible to draw a single vertical line through more than one point on either blue curve.

what's that

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐