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The graph of the quadratic function shown on the left is y = –0.7(x + 3)(x – 4). the roots, or zeros, of the function are . determine the solutions to the related equation 0 = –0.7(x + 3)(x – 4). the solutions to the equation are x =

In trapezoid efgh, m∠hef=(4x2+16)∘ and m∠gfe=(5x2+12)∘. find the value of x so that efgh is isosceles. i'm desperate.

Given the box plot, will the mean or the median provide a better description of the center? box plot with min at 10.5, q1 at 11.5, median at 12.5, q3 at 13.5, max at 15