The ordinate of a point is twice its abscissa . If its distance from the point (4,3) is √10 units ,then the coordinates of the point are ?

(1 , 2) and  (3 , 6)

Step-by-step explanation:

the point P : (x , y) -> (x , 2x)    ... ordinate of P point is twice its abscissa, y = 2x

√10 = √(x-4)² + (2x-3)²

5x² - 20x + 25 = 10

x² - 4x + 3 = 0

(x-1)(x-3) = 0

x = 1    or    x = 3

y = 2    or   y = 6

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]