What would be the denominator after rationalizing 7/(5√3-5√2) Please tell fast

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25

7 / (5√3-5√2)

= 7 / (5√3-5√2) * (5√3+5√2) / (5√3+5√2)

=7(5√3+5√2) / (5√3)²-(5√2)²

=35√3+35√2 / 75-50

=35√3+35√2 / 25

Thus the denominator of 7/(5√3-5√2) is 25.

Step-by-step explanation:

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Step-by-step explanation:

=> 7/(5√3-5√2) × (5√3+5√2)/(5√3+5√2)

=> 7(5√3+5√2)/75-50

=> (35√3+35√2)/25.

after rationalising the denominator is 25.

hope this helps you.

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b