You deposit $20.00 into an account that compounds interest continuously at a rate of 3.4%. To the nearest tenth of a year, how long will it take for it to grow to $150?

It would take 5.9 years to the nearest tenth of a year

Step-by-step explanation:

The formula of the compound continuously interest is A = P , where

A is the value of the account in t years

P is the principal initially invested

e is the base of a natural logarithm

r is the rate of interest in decimal

∵ Serenity invested $2,400 in an account

∴ P = 2400

∵ The account paying an interest rate of 3.4%, compounded continuously

∴ r = 3.4% ⇒ divide it by 100 to change it to decimal

∴ r = 3.4 ÷ 100 = 0.034

∵ The value of the account reached to $2,930

∴ A = 2930

→ Substitute these values in the formula above to find t

∵ 2930 = 2400

→ Divide both sides by 2400

∴  =

→ Insert ㏑ in both sides

∴ ㏑() = ㏑()

→ Remember ㏑() = n

∴ ㏑() = 0.034t

→ Divide both sides by 0.034 to find t

∴ 5.868637814 = t

→ Round it to the nearest tenth of a year

∴ t = 5.9 years

∴ It would take 5.9 years to the nearest tenth of a year

ok

step-by-step explanation: