Plz help! Solve systems of Equations by substitution
y = 6x -11
-2x - 3y = -7

x = 2

y = 1

Step-by-step explanation:

1) Re-arrange

(Solving for y)

-2x -3y = -7    -->  x3

6x - y = 11    -->  x1

-6x -9y = -21

6x -y = 11

-9y = -21

-y = 11

(-9y + -y) = (-21 + 11)

-10y = -10    

y = -10/-10

y = 1

2) Substitute

6x - 1 = 11

6x = 11 + 1

6x = 12

x = 12/6

x = 2

x = 2, y = 1

Step-by-step explanation:

Rearrange the second equation so it just works a little easier for you:

-2x - 3y = -7

rearranged to make y (with its constant) the subject:

3y = 7 - 2x

So we know what y equals. The question tells us y = 6x - 11. So substitute those values into the rearranged equation.

3y = 7 - 2x   becomes:

3(6x - 11) = 7 - 2x

because as stated in the question, y = 3x - 11.

Expand the brackets on the left-hand side:

18x - 33 = 7 - 2x

Rearrange to collect like terms:

18x = 7 + 33 - 2x

18x = 40 - 2x

18x + 2x = 40

20x = 40

x = 40/20

x = 2.

So now we know the value of x.

Let's input our new found value of x into one of the given equations, such as y = 6x - 11.

y = (6 * 2) - 11

y = 12 - 11

y = 1.

So y = 1.

You can test this by inputting these values into the other equation, for assurance.

-2x - 3y = -7 becomes:

(-2 * 2) - (3 * 1) = -7

(-4) - 3 = -7

-7 = -7

594 square inches

step-by-step explanation:

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