Cait can bike 32 miles in the same amount of time that Carl can bike 24 miles. If Cait bikes 2 mph faster than Carl, how fast does Cait bike?

Let t = time in hrs for both to go 32 mi

Let s = Carl's speed in mi/hr

s + 2 = Caits speed in mi/hr

Carl's equation:

(1) 24 = s · t

Cait's equation:

(2) 32 = (s+2) · t

(2) 32 = s · t + 2t

and

(1) s = 24/t

Plug (1) into (2)

(2) 32 = (24/t) · t + 2t

(2) 32 = 24 + 2t

(2) 2t = 8

(2) t = 4

and

(1) s = 24/4

(1) s = 6

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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answer: what are the following choices