The polynomial of degree 5, P(2), has leading coefficient 1, has roots of multiplicity 2 at x = 4 and x = 0, and a root of multiplicity 1 at 3 3.
Find a possible formula for P(x).
P(x)

Step-by-step explanation:

Each root corresponds to a linear factor, so we can write:

Any polynomial with these zeros and at least these multiplicities will be a multiple (scalar or polynomial) of this

Footnote

Strictly speaking, a value of  that results in is called a root of  

or a zero of . So the question should really have spoken about the zeros of  or about the roots of

i think 1: 2

step-by-step explanation: