Pls help me with this if you can

1) Let L = the larger # and S = the smaller #.

A large # is 5 more than twice a smaller #This gives Eq 1) L = 5 + 2S

Their sum is 80...This gives Eq 2) L + S = 80.

Substitute Eq 1) into Eq 2), you get

L + S = 80

5 + 2S + S = 80

3S = 75

S = 75 / 3 = 25

L = 5 + 2S

  = 5 + 2(25)

= 5 + 50

 = 55

2) [-7,2)

- Vocabulary

· Interval

A set of values between two endpoints.

· Inequality

A mathematical expression which shows that two quantites are not equal.

1) x = 25

2) 2(25)+5 = 55

-12<= x < 6

x <2 and x <= -7

Step-by-step explanation:

1) x

2) 2x + 5

x + 2x + 5 = 80

3x = 80 - 5

x = 75/3

x = 25

-24 <= 2x - 10

-24+10 <= 2x

-14/2 <= x

-7 <= x

2x -10< -6

2x < - 6 + 10

x < 4/2

x < 2

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

the answer is true.

step-by-step explanation: