2t/t-5 + 1/t-3 = 3 Help..

Step-by-step explanation:

Given equation is 2t/(t-5) + 1/(t-3) = 3

=> [2t(t-3)+1(t-5)]/(t-5)(t-3) = 3

=> (2t²-6t+t-5)/(t²-5t-3t+15) = 3

=> (2t²-5t-5)/(t²-8t+15) = 3

=> 2t²-5t-5 = 3(t²-8t+15)

=> 2t²-5t-5 = 3t²-24t+45

=>3t²-24t+45-2t²+5t+5 = 0

=> t²-19t+50 = 0

The standard form is t²-19t+50 = 0

answer: i think it is (1,-2)

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.