Find all of the zeros of If f(x) = x3 + 13x2 + 32x + 20 and f(-10)=0
pls help with this problem !

Step-by-step explanation:

Well you have one of the roots -- -10. Just by looking at it, -1 would seem to be another x intercept.

f(x) = (-1)^3 + 13(-1)^2 + 32(-1) + 20

f(x) = -1 + 13 - 32 + 20

f(x) = 0

So - 1 is also a root.

You should try -2

-2 * -10 - 1 = - 20

f(-2) = (-2)^3 + 13(-2)^2 + 32(-2) + 20

f(-2) =  -8 + 13 * 4 - 32(2) + 20

f(-2) = - 8 + 52 - 64 + 20

f(-2) = -72 + 72

f(-2) = 0

The zeros are

x = -10

x = -1

x = -2

the answer to this question is in the pic

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent