2) Find four consecutive integers such that twice the sum of the two greater integers is 91 more than three times the first integer X=
Equation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0