Mathematics, 26.10.2021 01:50 fatlip2429

2. Which number is a solution of the inequality? y+2> 8
a. -5
b. -6
c. 6
d. 7

Answers: 3

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Answer from: Quest

d. $180

step-by-step explanation:

if the dimensions of the room is 9ft by 12 ft, we have the area of the floor as,

$a=9\times 12=108\text {ft^2}$

so the area of the floor is 108 square feet, converting that into square yards we get,

$108 \times 0.1111= 12 \text{yd^2}$

the cost of carpet is $15 per square yard, therefore the cost of carpet for 12 square yards is,

$\$15 \times 12=\$180$

hence, the cost of carpet is $180.

assuming the dimensions of the room be,

15 ft by 12 ft

so, the area of the floor of that room is,

$a = 12 \times 15=180\text {ft}^2$

we can convert 180 square feet into square yards, we know that,

1 sq ft = 0.111 sq yard

so, 180 square feet is,

$180 \times 0.111=20 \text {yd}^2$

so the area of floor is 20 square yards.

now, the cost of carpet is 15 dollars per square yard, therefore the cost of carpet for 20 square yards is,

$\$15 \times 20= \$300$

so, it will cost $300.

Answer from: Quest

$4\left(625^4\right)\left(y^6\right)$

step-by-step explanation:

given expression is $4\sqrt{625^8y^{12}}$ .

now we need to simplify the given expression $\sqrt{20y^8}$ .

we know that square root is equivalent to the power 1/2. so that means we can take half of the exponents to get the square root of given expression.

$4\sqrt{625^8y^{12}}$

$=4\left(625^8y^{12}\right)^{\frac{1}{2}}$

$=4\left(625^8\right)^{\frac{1}{2}}\left(y^{12}\right)^{\frac{1}{2}}$

$=4\left(625^4\right)\left(y^6\right)$

expanding that will give a very very large number so let's keep answer in exponent form.

Answer from: Quest

use distributive property on all like terms and change your signs if you have a double negative or if you have positive/negative

Answer from: Quest

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

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2. Which number is a solution of the inequality? y+2> 8
a. -5
b. -6
c. 6

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