An ingot of metal shaped like the triangular prism below has a total mass of 25.6 kilograms. What is its density in grams per cubic centimeter.

453

Step-by-step explanation:

9514 1404 393

  20 g/cm³

Step-by-step explanation:

The volume of the prism is the product of the area of its triangular base and its height. The triangle area is ...

  A = 1/2bh

  A = 1/2(16 cm)(8 cm) = 64 cm²

The height of the prism is 20 cm, so its volume is ...

  V = Bh = (64 cm²)(20 cm) = 1280 cm³

The density of the ingot is the ratio of its mass to its volume.

  ρ = M/V = (25,600 g)/(1280 cm³) = 20 g/cm³

The density of the ingot is 20 g/cm³.

7.25

step-by-step explanation:

we know that 7 equals to 7.0. we also know that 1/4=0.25. so we can add the two together and we get 7.25