4 3/5 + 5 1/2
Help me please and thank you

Step-by-step explanation:

4 3/5 + 5 1/2= (10 1/10)

Step 1: Find the common multiple between the numbers, and simplify-

4 3/5=4 6/10 5 1/2= 5 5/10

Step 2: Convert to improper fractions-

4 6/10 as an improper fraction is 46/10 and 5 5/10 as an improper fraction is 55/10 (Formula for mixed numbers to improper fractions is denominator multiplied by whole number plus numerator)

Step 3: Add numerator of improper fractions, then add back denominator-

46+55=10 1 numerator:101 denominator:10 101/10

Step 4: Convert into mixed number-

101/10= 10 1/10

ANSWER: 10 1/10

10.1

Step-by-step explanation:

Conversion a mixed number 4 3/

5

to a improper fraction: 4 3/5 = 4 3/

5

= 4 · 5 + 3/

5

= 20 + 3/

5

= 23/

5

To find a new numerator:

a) Multiply the whole number 4 by the denominator 5. Whole number 4 equally 4 * 5/

5

= 20/

5

b) Add the answer from previous step 20 to the numerator 3. New numerator is 20 + 3 = 23

c) Write a previous answer (new numerator 23) over the denominator 5.

Four and three fifths is twenty-three fifths

Conversion a mixed number 5 1/

2

to a improper fraction: 5 1/2 = 5 1/

2

= 5 · 2 + 1/

2

= 10 + 1/

2

= 11/

2

To find a new numerator:

a) Multiply the whole number 5 by the denominator 2. Whole number 5 equally 5 * 2/

2

= 10/

2

b) Add the answer from previous step 10 to the numerator 1. New numerator is 10 + 1 = 11

c) Write a previous answer (new numerator 11) over the denominator 2.

Five and one half is eleven halfs

Add: 23/

5

+ 11/

2

= 23 · 2/

5 · 2

+ 11 · 5/

2 · 5

= 46/

10

+ 55/

10

= 46 + 55/

10

= 10.1

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.

d. corresponding side lengths in similar triangles are proportional in length.

step-by-step explanation: