What is the area of a triangle with vertices at (0, −2), (8, −2) , and (9, 1) ? Enter your answer in the box. units²

The area of a triangle is A=1/2*b*h

When we graph the vertices of the triangle on a graph, we see that the lowest points are at y=-2, and the highest point is at y=1.  Therefore, our height is 3.

The base of the triangle goes from (0,-2) to (8,-2), which gives us a length of 8 for our base.

A=1/2*(8)*(3)

A=12

or

12 square unit.

Step-by-step explanation:

Since, the area of a triangle having vertices ,  and  is,

Here, the vertices of the triangle are (0, −2), (8, −2) and (9, 1),

Hence, area of the given triangle is,

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step-by-step explanation:

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: