Caroline manages a team of six salespeople. It's a hard job, one filled with rejection; each person averages $500 in sales per day with a population standard deviation of $100. Caroline heard at a conference that if her employees started doing yoga in the morning, it would improve their mood and thus their sales performance. Caroline tries this; her six people started doing yoga in the morning. The day they started doing this, the average sales for those six employees was $550 per day. What is Caroline's conclusion as a result of this test of improvement

what is the graph

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

well the answer to that is xoxoxo

step-by-step explanation: