You have a bucket with 7 green ping pong balls, 13 black ping pong balls, and 9 red ping pong balls. Round to the fourth as needed
A. If 3 ping pong balls are selected at random with replacement, Input the probability they are all green.
Type out your work below.
B. If 3 ping pong balls are selected at random without replacement, Input the probability that none are black.

Step-by-step explanation:

A. In each drawing, the odds of choosing green is 7 / (7 + 13 + 9) = 7/29

with replacement, the odds in each drawing are the same

7/29•7/29•7/29 = 7³/39³ = 343 / 24,389

B.

Odds of drawing all non black balls is the sum of odds of drawing the following possible patterns

 ggg  +   ggr   +   grg   +   rgg  +   rrg   +    rgr   +    grr   +   rrr

(7•6•5 + 7•6•9 + 7•9•6 + 9•7•6 + 9•8•7 + 9•7•8 + 7•9•8 + 9•8•7) / 29•28•27 = 3,360/21,924

answer: b.48 for

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2