A box of candy has 7 red pieces, 3 orange, 2 yellow, and 8 blue pieces. You get to pick two pieces of candy. If you reach into the box without looking, what is the
probability that you will pick a blue piece, not replace it an then a red piece of
candy?

The probability is 2/8

28/95

There are 20 pieces of candy. First, you find the probability of drawing a blue piece which is 8/20 which is reduced to 4/5. Then you find the probability of drawing a red piece. Since you have removed a blue piece, there are now 19 pieces instead of 20. So, the probability of drawing a red piece is 7/19. Since the question is asking the probability of drawing a blue piece THEN a red piece you multiply the two fractions together since they are dependent upon each other. So, (4/5)(7/19)= 28/95.

Hope this helped. :)

Tbh i’m only here for the points