The equation of a circle is (x−2)^2+(y+6)^2=100. Find an equation to the circle that is internally tangent to the given circle and has center at (2, -10). I got an answer of (x-2)^2+(y+10)^2=36, and I entered it in an I got an incorrect answer. I think that I need multiple answers, because it says "Leave unused fields blank," even though I can't find any other possible answer. I don't know if it's a typo in the system or not.

found it xd it ok yt

26

step-by-step explanation:

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.