I need helppp plsss!!! Russell wants to buy hamburgers and fries for his friends, and he has $57.16 that he can spend. Each hamburger costs $3.29 including tax, and one order of fries costs $1.36 including tax. If Russell plans to purchase 12 hamburgers, which inequality could be used to find f, the number of orders of fries that Russell can purchase?
A.
$3.29 + $1.36f < $57.16

B.
12($3.29) + $1.36f > $57.16

C.
$3.29 + $1.36f > $57.16

D.
12($3.29) + $1.36f < $57.16

D. 12(3.29) + 1.36f < 57.16

Step-by-step explanation:

The variable f represents the number of fries Russell can purchase.

We already know he wants to purchase 12 hamburgers, and that hamburgers cost 3.29 each.

This means that the combined cost of all the hamburgers will be 12(3.29).

We also know fries cost 1.36 for every order. This means that Russell can spend 1.36f on fries with his budget 57.16.

This makes our inequality:

12(3.29) + 1.36f < 57.16

Keep in mind Russell has a constraint of having a budget of $57.16. This makes it odd for the solutions to the problem since this means it can also be equal to 57.16, but let's ignore that for now since there are no other solutions that include this detail. Russell must spend less than his budget of $57.16 in order to be able to buy what he wants. So the combined cost of the burgers and fries will be less than his budget of $57.16, not more than.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.