Help me please please please please please

This is the same as writing x^3-x^2

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Explanation:

We divide the two given polynomials. We can apply synthetic division.

The numerator polynomial is which is the same as

The sequence of coefficients are: {1,3,-4,0,0}. Those coefficients will be used to set up the synthetic division table in the top row.

The denominator polynomial x+4 means -4 is the test root since it's the solution to x+4 = 0. This -4 goes to the upper left corner.

Check out the diagram below.

The yellow cell in the bottom row represents the remainder. Everything else in the bottom row are coefficients to the quotient polynomial. The coefficients {1,-1,0,0} means we get which simplifies to and that's the final answer.

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Let's check the answer. Multiplying with should get us

Let's see if that happens.

We get the proper product we're after, so the answer is confirmed.

Basically we were given expressions for A and B and computed C = A/B to get the final answer C. This check section is us computing A = BC to confirm the answer.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b