[(3x-2)(x+6)]-[(x-1)(2x)]=103 steps

Let's solve your equation step-by-step.

(3x−2)(x+6)−(x−1)(2x)=103

Step 1: Simplify both sides of the equation.

x2+18x−12=103

Step 2: Subtract 103 from both sides.

x2+18x−12−103=103−103

x2+18x−115=0

Step 3: Factor left side of equation.

(x−5)(x+23)=0

Step 4: Set factors equal to 0.

x−5=0 or x+23=0

x=5 or x=−23

x=5 or x=−23

i believe the correct answer is b.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v