Calculate the mean and median of each data set, and determine what type of distribution it has. Data Set 1 5 8 9 6 3 2 10 8 5 4 3 Data Set 2 8 7 3 2 4 6 2 7 4 9 6
5 5.27 6 5.73 5.55 skewed right skewed left symmetric

Data Set 1:

Mean = 5.73

Median = 5

Data Set 2:

Mean = 5.34

Median = 5.64

Step-by-step explanation:

To find the mean, you need to add up all the data, and then divide this total by the number of values in the data.

Data Set 1:

5 + 8 + 9 + 6 + 3 + 2 + 10 + 8 + 5 + 4 + 3 = 63

There are 11 values, so you divide the total by 11:

63 ÷ 11 = 5.7272.. ≈ 5.73

Data Set 2:

8 + 7 + 3 + 2 + 4 + 6 + 2 + 7 + 4 + 9 + 6 + 5 + 5.27 + 6 + 5.73 + 5.55 = 85.55

There are 16 values, so you divide the total by 16:

85.55 ÷ 16 = 5.34

To find the median, you need to put the values in order, then find the middle value. If there are two values in the middle then you find the mean of these two values.

Data Set 1:

The numbers in order:

2, 3, 3, 4, 5, (5), 6, 8, 8, 9, 10

The middle value is marked in brackets, and it is 5.

So the median is 5

Data Set 2:

2, 2, 3, 4, 4, 5, 5.27, (5.55, 5.73), 6, 6, 6, 7, 7, 8, 9

This time there are two values in the middle. They have been in brackets The median is found by calculating the mean of these two values:

(5.55 + 5.73) ÷ 2 = 5.64

So, the median is 5.64

-TheUnknownScientist 72

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it