Let y=r(x) be continuous and differentiable. Assume r'(x)=0 r′(x)=0 at x=ax=a. If r'(x)<0 before x=a and r'(x)>0 after x=a

what must be true about r(a)?r(a)?
Choice 1: r(a) is a maximum value
Choice 2: r(a) is a minimum value
Choice 3: cannot determine based on this information

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Step-by-step explanation:

add an !

step-by-step explanation:

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)