An amusement park has two special annual membership passes. Plan A: For a single payment of $54.75, you receive an unlimited number of visits to the pak Plan B: Visits to the park cost $6.50 each plus a one-time membership fee of $18.95. Use algebra to determine how many visits you could make with Plan B before Plan A becom

I’m assuming we are considering ‘before Plan A becomes cheaper’

let n be the number of times you go to the park. Plan A’s cost doesn’t depend on how many times you enter the park,

18.95 + 6.50n > 54.75

6.50n > 54.75 - 18.95

6.50n > 35.8

n > 35.8/6.50 ~ 5.508

You obviously can’t ‘half visit’ a place. So we either round up or down to the nearest whole number.

But wording here is important.

‘before’ basically implies, in this context, ‘what is the limit until x’.

Imagine the meme ‘so the limit is 412 chicken nuggets’ when some guy was paralysed after eating 413 = 412 + 1 nuggets

Using the same logic, ‘the limit is’:

n = 5 visits (round down to the nearest whole)