The tension t in a spring varies directly with the distance d the spring is stretched. If the tension is 26 pounds when the spring is stretched 4 inches, find the tension when the spring is stretched twice as
far.

t = 21d

Step-by-step explanation:

Here tension and distance are denoted t by d  and  respectively. Since  t varies directly with d , then the relation between  t and d is k=td Given that, for the tension 42 pounds, the spring is stretched 2 inches. Substituting  t = 42 and d= 2 into  t = kd find the value of k . Therefore,

42= K (2)

K= 21

Thus the relationship is t = 21d

(Hope this helps can I pls have brainlist (crown)☺️)

hiking down a winding trail.

step-by-step explanation:

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4