During the last lap of a dirt race, the speed of a car is given by the function v(t) = – t2 + 16t, where v is expressed in meters/second and t is in seconds. What is the maximum speed that the car achieved during the last lap?

64 m/s at 8 seconds.

Step-by-step explanation:

Think of the given equation as a function of time for velocity.  Thus, by simply graphing the function, you find a maximum at (8, 64).

Hope it helps :)

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680