Relations mapping domain values to range values can be described as one-to-one or not one-to-one. If one x-value maps to many y-values (one-to-many), does the relation represent a function? If the x- and y-values are reversed, does the relation represent a function? Explain.

If the relation is not one-to-one, does the relation represent a function? If the x- and y-values are reversed, does the relation represent a function? Explain.

If the relation is one-to-one, does the relation represent a function? If the x- and y-values are reversed, does the relation represent a function? Explain.

a. In a one-to-many relation, at least one

▼

output

input

value maps to

▼

more than one

exactly one

the same

at least one

no more than one

▼

input

output

value. This means a one-to-many relation

▼

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^

i am not sure :

step-by-step explanation:

x-150=475   x=625

step-by-step explanation:

if the bike after the sale ($150) is $475 then just simply add 150 to 475.