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Mathematics, 13.11.2021 14:00 amazinga

2sin²θ+2sin²2θ = 3sin²2θ
Solve the equation for 0≤θ< 2π
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Answers: 1

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2sin²θ+2sin²2θ = 3sin²2θ
Solve the equation for 0≤θ< 2π
Show steps...
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