Mathematics, 13.11.2021 14:00 ryevins3
Work is shown to solve for the system of equations.
Why does the answer for y indicate that the system has no real number solutions.
O The solution does not solve for X first.
O The values for Y are square roots of negative numbers.
O The values for y have square roots.
O The values for Y have a positive and a negative value.
Answers: 3
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Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
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Work is shown to solve for the system of equations.
Why does the answer for y indicate that the sy...
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