What is an equation of the line perpendicular to y=1/5x+2 That contains (15, -4)?

PLS HELP

y+4=-5(x-15)

Step-by-step explanation:

Use point-slope form:

y-y1=m(x-x1)

m is the slope

x1 is the x coordinate of the point that the line contains

y1 is the y coordinate of the same point

We are already given the coordinates of the point (15, -4), so we just need m, the slope.

We are given that equation of the line is perpendicular to line y=1/5x+2. Perpendicular lines have slopes that are negative reciprocals of one another. The slope of y=1/5x+2 is 1/5, so all we need to do it get the negative reciprocal of 1/5.

The negative reciprocal of 1/5 would be -5. (switch the numerator and denominator and slap on a negative)

Now we know

m is -5

x1 is 15

y1 is -4,

so plug those into point-slope form: y-y1=m(x-x1)

y-(-4)=-5(x-15)

y+4=-5(x-15) is the answer

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