Consider the LTS: M ≡ h{s0, s1, s2, s3}, {s0}, {(s0, s1),(s0, s3),(s1, s1),(s1, s2),(s2, s0),(s2, s3),(s3, s0)}, Li
where L assigns {p1, p2} to s0, {p3} to s1, {p1, p4} to s2, and {p2, p3} to s3. For each of the following
CTL wffs φ, determine whether or not M φ. If the answer is yes, briefly justify your answer;
otherwise, provide a counterexample trace/path.
(a) AFp2
(b) AG(EF(p1 ∨ p3))
(c) EX(EXp3)
(d) AG(AFp2)

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.

step-by-step explanation:

gym b charges $1.05 less per hour than gym a.