WILL GIVE BRAINLIEST AND WORTH 20 POINTS! A train leaves Los Angeles at 2 p. m. heading north at 50 mph. If the next train leaves three hours later and also heads north at 60 mph, at what time will the second train catch up with the first?

The Second train will catch up with the first train after 15 hours which is 8a.m the following morning.

First train :

Departure time = 2 pm

Speed = 50 mph

Second train :

Departure time = 2 pm + 3 hours = 5 pm

Speed = 60 mph

Distance = speed × time

Distance already covered by first train before the departure of the second = 50 mph × 3 hpird = 150 miles

The number of hours needed for second train to catch up will be h;

(60 × h) = (50 × h) + 150

60h = 50h + 150

60h - 50h = 150

10h = 150

h = 150/ 10

h = 15

Second train will catch up after 15 hours :

Hence, time will be : (5pm + 15 hours) = 8 a.m the following morning.

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(NOT MY ANSWER)

the second train will Cath up with the first after 15 hours hence time will be at (5pm+15hours= 8:00am

Step-by-step explanation:

the circle one

113.1

step-by-step explanation:

v=4

3πr3=4

3·π·33≈113.09734