(y+3):(y+5)=k:1 show that y=5k-3/1-k

  y = (5k -3)/(1 -k)

Step-by-step explanation:

  (y +3)/(y +5) = k/1

  y +3 = k(y +5) . . . . . multiply by (y+5)

  y +3 = ky +5k . . . . . eliminate parentheses

  y -ky = 5k -3 . . . . . . subtract (ky+3)

  y(1 -k) = 5k -3 . . . . . factor out y

  y = (5k -3)/(1 -k) . . . . divide by the coefficient of y

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Additional comment

When this is written in plain text, as above, the parentheses are essential grouping symbols for the numerator and denominator. If the equation is typeset:

then no parentheses are required, because the fraction bar serves to identify the numerator and denominator expressions.

When written without parentheses,

  y = 5k -3/1 -k = 5k -(3/1) -k = 4k -3 . . . . not the same as above

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

answer:  

step-by-step explanation:

odd numbers are only divisible by 1 and itself.

even numbers are divisible by more than 1 and itself.

for example 6 is even because it is divisible by more than 1 and its self. 1 x 6= 6 ; 2 x 3= 6

and 7 is odd because only 7 x 1 equals seveb