The factorization of 12a^2b+15ab^2 gives: 1 point
3ab(4a+5b)
3b(4a + 5b)
3a(4a+5b)
3ab(4ab+5)
The factorization of 12x+36 is
1 point
12(x+3)
12(3x)
12(3x+1)
x(12+36x)
On factorising 14pq + 35pqr, we get:
1 point
pq(14+35r)
p(14q+35qr)
7pq(2+5r)
q(14p+35pr)
The factors of x^2 +xy+8x+8y are:
1 point
(x+y) (x+8)
(x+2y) (x+8)
(2x+y) (x+8)
(x+y) (2x+8)
Which of the following are the factors of a^2 + ab +bc + ca
1 point
(b + c) (c + a)
(a + b) (a + c)
a(a + b + c)
(a + b) (b + c).
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answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

well the answer to that is xoxoxo

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