Given: JK LK: ZJYL and LXJ are right angles. Prove: JY LX

Proof:

Statements

Reasons

1.

?

1. ZKILE ZKLU

2. JL = LJ

2.

?

3. Given

3. LJYL and CLXJ

are rt.

4. LJYL ZLXJ

4.

2

5. AJYL ALXI

S.

?

6. JY LX

6.

?

Which justification belongs in Step 1?

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true

mnkjn

step-by-step explanation: