Suppose that the probability of a bit error in transmission over a binary symmetric channel is 0.001. What is the probability that when a codeword with eight bits is sent from a code with minimum distance five, the bit string received is decoded as the codeword sent (when nearest neighbor decoding is used)?

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

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6 spoons of sugar for every 21 cups of flour

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