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Mathematics, 25.11.2021 07:00 nicoleh2015

\frac{dh}{dt}  =  -  \sqrt{5h} Determine
at h=16

I have attempted this and keep on getting about -0.28, but that is not an option.


\frac{ {d}^{2}h }{d {t}^{2} }

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Determine

at h=16

I have attempted this and keep on getting about -0.28, bu...
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