Mathematics, 25.11.2021 07:20 TropicalFan
PLEASE HELP giving brainest Consider the system of equations shown below consisting of one linear and one quadratic equation. y=4x-5 and y=2x^2-5x-10 Find the intersection points of this system algebraically.
Answers: 1
![\begin{cases} y = 4x - 5\\ y = 2x^2-5x-10 \end{cases}\qquad \stackrel{y}{4x-5}~~ = ~~\stackrel{y}{2x^2-5x-10} \\\\\\ -5=2x^2-9x-10\implies 0=2x^2-9x-5 \\\\\\ 0=(x-5)(2x+1)\implies \begin{cases} 0 = x-5\\ 5 = x\\[-0.5em] \hrulefill\\ 0 = 2x+1\\ -1=2x\\ -\frac{1}{2}=x \end{cases}](/tpl/images/2569/4610/c9895.png)
![y = 4(\stackrel{x}{5})-5\implies y = 20-5\implies y = 15 \\\\\\ y = 4\stackrel{x}{\left( -\frac{1}{2} \right)}-5\implies y = -2-5\implies y = -7 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{intersection points}}{(5~~,~~15)\qquad \left(-\frac{1}{2}~~,~-7 \right)}~\hfill](/tpl/images/2569/4610/6a302.png)
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PLEASE HELP giving brainest Consider the system of equations shown below consisting of one linear an...
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