ABCD is a parallelogram and X and Y are any point on CD and AD respectively. Prove that triangle AXB and triangle BYC are equal in area. Prove that

See answer below

Step-by-step explanation:

ABCD is a parallelogram                     Given

BC ≅ AD; AB ≅ DC                             opposite sides of a parallelogram ≅

Δ AXB = 1/2 (AB)(AD)                           Formula for the area of a Δ

Δ BYC = 1/2 (BC) (DC)                           Formula for the area of a Δ

1/2 (AB)(AD)= 1/2(BC)(DC)                      Substitution

∴ Area of Δ AXB = Area of ΔBYC

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0