The second of three numbers is 5 times the first. The third number is 3 more than the second. If the second is decreased by twice the third, the result is -21. Find the Three numbers

1st number is 6

2nd number is 30

3rd number is 33

Step-by-step explanation:

Let x be the first number.

The second of three numbers is 5 times the first = 5x

The third number is 3 more than the second = 5x + 3

If the second is decreased by twice the third, the result is -21.

Multiply the third number by 2.

2(5x + 3)

= 10x + 6

Subtract the second number to it.

(5x)-(10x + 6) = -21

-5x - 6 = -21

Use APE or Addition Property of Equality

-5x = -21 + 6

-5x = -15

Use DPE or Division Property of Equality to get the value of x

x = 3

Now put the value of x in the equation

first number(x) = 6

second number(5x) = 5(6) = 30

third number(5x + 3)

5(6) + 3

30 + 3 = 33

answer:

your answer is: c. 196 7/8 in^3.