A rocket is 13 feet from a satellite when it begins accelerating away from the satellite at a constant rate of 6 feet per second per second. The distance, in feet, between the rocket and the satellite is modeled by P=3t^2+13 where t is the number of seconds since the rocket started accelerating. Use the model to find and interpret the result when t=4

the answer is 54 sq. ft. i just did this question, on odyssey ware, and it was right. make brainliest.

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)

below

step-by-step explanation:

1. 5/1

2. 10/16

3. 90/2

4. 1/20

5. 3/1

6. 14/24

7. 1/4

8. 18/10