An object is launched straight up into the air at an initial velocity of 64 feet per second. It is launched from a height of 6 feet off the ground. Its height H in feet, at t seconds is given by the equation H=-16t^2*64t+6. Find all times t that the object is at a height of 54 feet off the ground.

.19875994384

step-by-step explanation:

1699/ 8548

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: