Can you help me! Determine the solution to the following one-variable linear equation:

a. 4a - 11 = 2a + 3
b. 3z + 12 = 15
c. 2 - 6b = 20
d. 3y - 5 = 27 - y

Hi,

4a - 11 = 2a + 3

4a - 11 + 11 = 2a + 3 + 11

4a = 2a +14

4a - 2a = 2a - 2a + 14

2a = 14

2a / 2 = 14 / 2

a = 7

3z + 12 = 15

3z + 12 - 12 = 15 - 12

3z = 3

3z / 3 = 3 / 3

z= 1

2 - 6b = 20

2 - 2 - 6b = 20 - 2

- 6b = 18

6b = - 18

6b / 6 = -18 / 6

b= -3

3y - 5 = 27 - y

3y - 5 + 5 = 27 - y + 5

3y = - y +32

3y + y = - y + y +32

4y = 32

4y / 4 = 32 / 4

y= 8

✅(◠‿◕)

it has changed from the width and the height.

step-by-step explanation:

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3