At 6:00 AM, the temperature was 5°F below zero. At noon the temperature was 2ºF above zero At 6.00 PM the temperature was 7°F above zero. Which equation shows the change in temperature from 6:00 AM to 6:00 PM.? D |-3-^ prime prime |=-^ prime2 =32^ prime = |- 5 - 2| = |- 7| = 7F B |2 - 7| = |- 5| = 5F C A 15 - 7 = 1 - 21 = 2 degrees * F

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

70

step-by-step explanation:

what level of math? also i don't need to be paid if i can you.