What is the distance between the points (3,7) and (15,6) on a coordinate plane ?

12.04

Step-by-step explanation:

the distance between two points in the x-axis

15-3 = 12

the distance between two points in the y-axis

7-6=1

using Pythagorean theory

a²+b²=c²

12²+1²=c²

144+1=c²

145=c²

√145=√c²

12.04=c

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

b

step-by-step explanation: