Determine if the graph can represent a polynomial function. If so, assume that the end behavior and all turning points are represented in the graph.
(a) If the graph is a polynomial, determine the minimum degree of the polynomial.
(b) If the graph is a polynomial, determine whether the leading coefficient is positive or negative based on the end behavior and
whether the degree of the polynomial is odd or even.
(c) If the graph is a polynomial, approximate the real zeros of the function, and determine if their multiplicities are even or odd.

the mean and mad

step-by-step explanation:

table 3 represents a direct variation function. : )

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: