Mathematics, 02.12.2021 05:40 mom9032
To prove that 3√⋅12 is irrational, assume the product is rational and set it equal to ab, where b is not equal to 0. Isolating the radical gives 3√=2ab. The right side of the equation is
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. Because the left side of the equation is
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, this is a contradiction. Therefore, the assumption is wrong, and the product is
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.
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To prove that 3√⋅12 is irrational, assume the product is rational and set it equal to ab, where b is...
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